Instant Download Oracle : 1Z0-007 Questions & Answers as PDF & Test Engine
Updated: Sep 17, 2026
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Oracle 1Z0-007 Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Subqueries | 10% | - Single-row and multi-row subqueries - Using IN, ANY, ALL operators |
| Topic 2: Writing Basic SQL SELECT Statements | 15% | - Executing basic SELECT statements - Capabilities of SQL SELECT statements - SQL vs iSQL*Plus commands |
| Topic 3: Restricting and Sorting Data | 12% | - Limiting rows with WHERE clause - Sorting results with ORDER BY - Using substitution variables |
| Topic 4: Aggregating Data Using Group Functions | 13% | - Using COUNT, SUM, AVG, MAX, MIN - GROUP BY clause - Filtering groups with HAVING |
| Topic 5: Displaying Data from Multiple Tables | 15% | - Equijoins and non-equijoins - Outer joins and self-joins - ANSI/ISO SQL99 joins |
| Topic 6: Single-Row Functions | 18% | - Character, number, and date functions - Conditional expressions (NVL, DECODE) - Conversion functions (TO_CHAR, TO_NUMBER, TO_DATE) |
| Topic 7: Manipulating Data | 8% | - INSERT, UPDATE, DELETE statements - Transaction control (COMMIT, ROLLBACK, SAVEPOINT) |
| Topic 8: Creating and Managing Tables | 9% | - Data types and constraints - Managing indexes, sequences, synonyms, views - CREATE, ALTER, DROP, RENAME tables |
Oracle Introduction to Oracle9i: SQL Sample Questions:
Examine the structure of the EMPLOYEES table:
What is the correct syntax for an inline view?
- A. SELECT a.last_name, a.salary, a.department_id,
- B. SELECT a.last_name, a.salary, a.department_id
FROM employees a
WHERE a.salary =
(SELECT max(salary)
FROM employees b
WHERE a.department_id = b.department_id); - C. SELECT a.last_name, a.salary, a.department_id
FROM employees a
WHERE (a.department_id, a.salary) IN
(SELECT department_id, a.salary) IN
(SELECT department_id max(salary)
FROM employees b
GROUP BY department_id
ORDER BY department_id); - D. SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))
- E. maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary < b.maxsal;
Correct Answer: A 🗳️
Explanation: Only visible for ActualVCE members. You can sign-up / login (it's free).
Which clause would you use in a SELECT statement to limit the display to those employees whose salary is greater then 5000?
- A. HAVING SALARY > 5000
- B. WHERE SALARY > 5000
- C. GROUP BY SALARY > 5000
- D. ORDER BY SALARY > 5000
Correct Answer: B 🗳️
Explanation: Only visible for ActualVCE members. You can sign-up / login (it's free).
Which three are true? (Choose three.)
- A. A MERGE statement is used to merge the data of one table with data from another.
- B. A MERGE statement can be used to update existing rows in a table.
- C. A MERGE statement replaces the data of one table with that of another.
- D. A MERGE statement can be used to insert new rows into a table.
Correct Answer: A,B,D 🗳️
Explanation: Only visible for ActualVCE members. You can sign-up / login (it's free).
The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER(4)
ENAME VARCHAR2 (25)
JOB_ID VARCHAR2(10)
Which SQL statement will return the ENAME, length of the ENAME, and the numeric position of the letter "a" in the ENAME column, for those employees whose ENAME ends with a the letter "n"?
- A. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, ,-1,1) FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
- B. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, -1, 1) = 'n';
- C. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, 1, 1) = 'n';
- D. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, 'a') FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
Correct Answer: D 🗳️
Explanation: Only visible for ActualVCE members. You can sign-up / login (it's free).
The CUSTOMERS table has these columns:
The CUSTOMER_ID column is the primary key for the table.
Which two statements find the number of customers? (Choose two.)
- A. SELECT COUNT(customers) FROM customers;
- B. SELECT COUNT(customer_id) FROM customers;
- C. SELECT TOTAL(*) FROM customers;
- D. SELECT TOTAL(customer_id) FROM customers;
- E. SELECT COUNT(*) FROM customers;
- F. SELECT TOTAL(customer_name) FROM customers;
Correct Answer: B,E 🗳️
Explanation: Only visible for ActualVCE members. You can sign-up / login (it's free).
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